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<p>3 sets of Hoops <del>each</del><add>all</add> 20 inches high.</p> | <p>3 sets of Hoops <del>each</del><add>all</add> 20 inches high.</p> | ||
<p>First set No central < | <p>First set No central <unclear>arch</unclear><lb/> | ||
1 of 1/4 | <del>1 of 1/4 inch thick diameter</del></p> | ||
<p>First Set No Central Area</p> | <p>First Set No Central Area</p> | ||
<p><del>1 20 foot</del></p> <p><add> | <p><del>1 20 foot</del></p> <p><add>Inches</add> Diameter from outside to outside</p> | ||
<p>Foot <del>1</del><lb/> | <p>Foot <del>1</del><lb/> | ||
Line 19: | Line 19: | ||
4 foot x 2= 8 + 38 = 46 12 1/2</p> | 4 foot x 2= 8 + 38 = 46 12 1/2</p> | ||
<p>Exterior | <p>Exterior Arch<lb/> | ||
12 1/2 foot <gap/> | 12 1/2 foot <gap/> in thickness<lb/> | ||
= 1<del>3</del>4 1/2 x 2 - 29 + 46 = 75 19</p> | = 1<del>3</del>4 1/2 x 2 - 29 + 46 = 75 19</p> | ||
3 sets of Hoops eachall 20 inches high.
First set No central arch
1 of 1/4 inch thick diameter
First Set No Central Area
1 20 foot
Inches Diameter from outside to outside
Foot 1
Boundary of the Lodge} 20 _ _ _5
20 foot _ _ 938 8 1/2 1 1/8 high only
Interned Area
Protracted
4 foot x 2= 8 + 38 = 46 12 1/2
Exterior Arch
12 1/2 foot in thickness
= 134 1/2 x 2 - 29 + 46 = 75 19
Second set with a central Area
Central Area
Diameter 15 foot 3 3/4
Lodge Diameterbreadth
15 x 2 or 30 + 15 = 45 11 1/2
Intermediate are 9 + 2
= 18 + 45 = 63 15 3/4 1 1/8 high only
Protracted Positions.
Cells inward boundary
4 x 2 = 8 + 63 = 71 17 3/4
Outward boundary 1312 1/2 + 2
(thickness of walls) = 13>1/2</add> x 24<add
= 29 + 71 = 100 25
Wanted Human figures Models
1. Man standing
2. do sitting
3. do kneeling
Identifier: | JB/157/032/001"JB/" can not be assigned to a declared number type with value 157. |
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157 |
panopticon |
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032 |
cancelled |
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001 |
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rudiments sheet (brouillon) |
2 |
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recto |
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jeremy bentham |
[[watermarks::l munn [britannia with shield emblem]]] |
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benjamin constant |
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53402 |
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