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<p> | <p>Qu. The degree of Conducting Power; & heat conducted</p> | ||
<p>1. In the Case of Ice, which will always remain one uniform temperature.<lb/> | <p>1. In the Case of Ice, which will always remain of one uniform temperature.<lb/> | ||
Quiescent State must be the following in a substance of uniform conducting power.</p> | Quiescent State must be the following in a substance of uniform conducting power.</p> | ||
N.B. The | N.B. The no.<hi rend="superscript">s</hi> express the excess of the temperature above y<hi rend="superscript">+</hi> of ice.<lb/> | ||
Air |<lb/> | Air |<lb/> | ||
<p>20<hi rend="superscript">o</hi>=A |19<hi rend="superscript">o</hi>|18<hi rend="superscript">o</hi>|17<hi rend="superscript">o</hi>| 16<hi rend="superscript">o</hi>|15<hi rend="superscript">o</hi>|14<hi rend="superscript">o</hi>| 13<hi rend="superscript">o</hi>|12<hi rend="superscript">o</hi>|11<hi rend="superscript">o</hi> |10<hi rend="superscript">o</hi>|9<hi rend="superscript">o</hi>|8<hi rend="superscript">o</hi> |7<hi rend="superscript">o</hi>|6<hi rend="superscript">o</hi>|5<hi rend="superscript">o</hi> |4<hi rend="superscript">o</hi>|3<hi rend="superscript">o</hi>|2<hi rend="superscript">o</hi>|1<hi rend="superscript">o</hi>|0<hi rend="superscript">o</hi>=B</p> | <p>20<hi rend="superscript">o</hi>=A |19<hi rend="superscript">o</hi>|18<hi rend="superscript">o</hi>|17<hi rend="superscript">o</hi>| 16<hi rend="superscript">o</hi>|15<hi rend="superscript">o</hi>|14<hi rend="superscript">o</hi>| 13<hi rend="superscript">o</hi>|12<hi rend="superscript">o</hi>|11<hi rend="superscript">o</hi> |10<hi rend="superscript">o</hi>|9<hi rend="superscript">o</hi>|8<hi rend="superscript">o</hi> |7<hi rend="superscript">o</hi>|6<hi rend="superscript">o</hi>|5<hi rend="superscript">o</hi> |4<hi rend="superscript">o</hi>|3<hi rend="superscript">o</hi>|2<hi rend="superscript">o</hi>|1<hi rend="superscript">o</hi>| 0<hi rend="superscript">o</hi>=B</p> | ||
<p>Let the higher temperature, viz.y<hi rend="superscript">+</hi> of the air be = A<lb/> | <p>Let the higher temperature, viz.y<hi rend="superscript">+</hi> of the air be = A<lb/> | ||
the lower - - - or y<hi rend="superscript">+</hi> or y<hi rend="superscript">-</hi> ice = B</p> | the lower - - - or y<hi rend="superscript">+</hi> or y<hi rend="superscript">-</hi> ice = B</p> | ||
<p>C=Conducting Power<lb/> | |||
S.=surface</p> | |||
<p>Their difference = A - <del>BD</del> B = D</p> | <p>Their difference = A - <del>BD</del> B = D</p> | ||
<p>Difference in temperature between two contiguous minute strata = d</p> | <p>Difference in temperature between two contiguous minute strata = d</p> | ||
<p>Number of Strata = N <hi rend="superscript">.</hi>=. thickness of the | <p>Number of Strata = N <hi rend="superscript">.</hi>=. thickness of the conductor.</p> | ||
<p>Time necessary for the equilibrium being restored between two contiguous<lb/> | <p>Time necessary for the equilibrium being restored between two contiguous<lb/> | ||
strata; that is for the transmission of d/2 of heat in the direction of<lb/> | strata; that is for the transmission of d/2 of heat in the direction of<lb/> | ||
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<p>Let t be <hi rend="superscript">.</hi>=. 1/d which is probably the law of communication of<lb/> | <p>Let t be <hi rend="superscript">.</hi>=. 1/d which is probably the law of communication of<lb/> | ||
temperature</p> | temperature</p> | ||
<p>H <hi rend="superscript">.</hi>=. & 1/txCs but t <hi rend="superscript">.</hi>=. 1/d therefore H <hi rend="superscript">.</hi>=. SddC <hi rend="superscript">.</hi>=. D<hi rend="superscript">2</hi>CS/N<hi rend="superscript">2</hi></p> | <p>H <hi rend="superscript">.</hi>=. d/2 & 1/txCs but t <hi rend="superscript">.</hi>=. 1/d therefore H <hi rend="superscript">.</hi>=. SddC <hi rend="superscript">.</hi>=. D<hi rend="superscript">2</hi>CS/N<hi rend="superscript">2</hi></p> | ||
<p>Therefore the heat transmitted thro' any conducting substance of uniform<lb/> | <p>Therefore the heat transmitted thro' any conducting substance of uniform<lb/> | ||
structure is as the conducting power multiplied by the square of the<lb/> | structure is as the conducting power multiplied by the square of the<lb/> | ||
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<p>Probably the same formula applied to the other cases as well as to this.</p> | <p>Probably the same formula applied to the other cases as well as to this.</p> | ||
<p>By the help of this formula it would perhaps be easy to<lb/> | <p>By the help of this formula it would perhaps be easy to<lb/> | ||
calculate the quantity of ice required for y< | calculate the quantity of ice required for y<hi rend="superscript">-</hi> annual stock - by a few<lb/> | ||
direct experiments.</p> | direct experiments.</p> | ||
<p>N.B. The formula also furnishes an easy method of<lb/> | <p>N.B. The formula also furnishes an easy method of<lb/> | ||
ascertaining the conducting powers of bodies with great precision<lb/> | ascertaining the conducting powers of bodies with great precision<lb/> | ||
as the different | as the different capacities of bodies for heat will influence the <unclear>experim<hi rend="superscript">t</hi></unclear>.</p><pb/> | ||
Qu. The degree of Conducting Power; & heat conducted
1. In the Case of Ice, which will always remain of one uniform temperature.
Quiescent State must be the following in a substance of uniform conducting power.
N.B. The no.s express the excess of the temperature above y+ of ice.
Air |
20o=A |19o|18o|17o| 16o|15o|14o| 13o|12o|11o |10o|9o|8o |7o|6o|5o |4o|3o|2o|1o| 0o=B
Let the higher temperature, viz.y+ of the air be = A
the lower - - - or y+ or y- ice = B
C=Conducting Power
S.=surface
Their difference = A - BD B = D
Difference in temperature between two contiguous minute strata = d
Number of Strata = N .=. thickness of the conductor.
Time necessary for the equilibrium being restored between two contiguous
strata; that is for the transmission of d/2 of heat in the direction of
from A to B, = t H = heat communic.d during the time T given.
Let t be .=. 1/d which is probably the law of communication of
temperature
H .=. d/2 & 1/txCs but t .=. 1/d therefore H .=. SddC .=. D2CS/N2
Therefore the heat transmitted thro' any conducting substance of uniform
structure is as the conducting power multiplied by the square of the
difference of temperature between the two bodies which maintain their heat
temperature - directly,
And as the squares of the thickness of the conductor inversely
It is also directly as the surface, that is or as the square of y diameter
—
Probably the same formula applied to the other cases as well as to this.
By the help of this formula it would perhaps be easy to
calculate the quantity of ice required for y- annual stock - by a few
direct experiments.
N.B. The formula also furnishes an easy method of
ascertaining the conducting powers of bodies with great precision
as the different capacities of bodies for heat will influence the experimt.
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Identifier: | JB/106/065/003"JB/" can not be assigned to a declared number type with value 106. |
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1795 |
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106 |
frigidarium |
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065 |
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003 |
sources of cold / sources of heat / economy of temperature |
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copy/fair copy sheet |
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recto |
f2 / / / |
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fr4 |
pot 1796 |
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fc6 |
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1796 |
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34653 |
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