JB/135/084/003

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Prob.
XXI
n. 371
p. 272

The
diameter
of a
globe
being
given,
to find
the
superficies.

Rule

Find
the
circumference
of a
great
circle
upon
the
globe
by
article
356
multiply
the
circumference
by the
diameter,
and
the
product
will
express
the
superficies.

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Prob.
XXI
n. 372
p. 273

The
diameter
or semidiameter
of
a globe
being
given,
to find
the
superficies.

Rules

Multiply
3,1416
by the
square
of the
diameter &
the
product
will
give
the
superficies.
or
2. Multiply
the
square
of the
semidiameter
by 88
divide
the
product
by 7,
and
the
quotient
will
give
the
superficies

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Prob.
XXII
n. 373
p. 274

To
find
the superficies
of a
segment
of a
globe,
made
by the
section
of a
plain

Rule

Multiply
the
circumference
of the
globe
by the
height
of the
segment
and
the
product
will
give
the
superficies.

Prob
XXIII.
n. 375
p. 276

To
find
the solidity
or content
of a
cube.

Rule

Multiply
the
square
of a
side
by the
side,
and
the
product
will
express
the
content.

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Prob
XXIV.
n. 376
p. 277

To
find
the
content
of a
prism

Rule

Multiply
the area
of
the
base
by the
height
or altitude
and
the
product
will
express
the
content.

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Prob.
XXV.
n. 377
p. 280

To
find
the
content
of a
wall
in
square
rods
of a
brick
and
half
thick

Rule

Multiply
the
area
of the
wall
in feet
by
the
number
of
half
bricks
in
thickness,
& divide
the
product
by 816
and
the
quotient
will
express
the
content
required

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Prob
XXVI
n. 378
p. 281

To find
the
content
of a
pyramid.

Rule

Multiply
the
area
of the
base
by a
third
part
of the
altitude,
and
the
product
will
give
the
content

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Prob
XXVII
n. 379
p. 282

To
find
the
content
of a
wedge
which
is a
solid
contained
under
five
plains
the
back
or base
is a
rectangle
or
oblong
and
the
four
sides
terminate
in
the
edge
E.F.
being
a strait
line
parallel &
equal
to a
side
of the
base.

Rule

Multiply
the
area
of the
base
by
half
the
altitude
of the edge.
and
the
product
will
give
the
content

---page break---

Prob.
XXVIII
n. 380
p. 283

To
find
the
content
of
a pavilion
roof
which
is a
solid
contained
under
five
plains
the base
is a
rectangle
or oblong
and
the
four
sides
terminate
in a
ridge
parallel
to
a side
of the
base,
but
unequal
to it.

Rule

To the
length
of the
ridge
add
twice
the
side
of the
base
which
is parallel
to it.
Multiply
the
sum
by the
other
side
of the
base,
and
the
product
which
arises
by a
sixth
part
of the
altitude,
and the
second
product
will
give ye
content

---page break---

Prob.
XXIX
n. 381
p. 284

To find
the
content
of the
frustum
of a
square
pyramid,
made
by a
section
parallel
to the
base

Rule

To the
areas
of the
ends
add
the
product
of their
sides,
multiply
the
sum
by a
third
part
of the
altitude
and
the
product
will
give
the
content.

---page break---

Prob.
XXX
n 382
p. 285

To
find
the
content
of
a prismoid
being
a solid
contained
under
six
plains
the bases
or
end
are
parallel
rectangles
or oblongs
and
the
four
sides
are
quadrangles.

Rule

To the
areas
of the
ends
add
the
product
of the
sums
of their
lengths
& breadths;
and multiply
this
sum
by a
sixth
part
of the
altitude
and
the
product
will
give
the
content.

---page break---

Prob.
XXXI
n. 383
p. 286

To
find
the
content
of a
cylinder.

Rule

Multiply
the
area
of the
base
by the
altitude
of the
cylinder,
and
the
product
will
express
the
content.

---page break---

Identifier: | JB/135/084/003"JB/" can not be assigned to a declared number type with value 135.
Date_1		Marginal Summary Numbering
Box	135	Main Headings	posology
Folio number	084	Info in main headings field	geometry - iv
Image	003	Titles
Category	copy/fair copy sheet	Number of Pages
Recto/Verso	recto	Page Numbering
Penner		Watermarks
Marginals		Paper Producer
Corrections		Paper Produced in Year
Notes public		ID Number	46202
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